Casey, a second grade boy, is raising caterpillars which each have the same number of legs. Let C represent the number of legs that the caterpillars Casey has, and L represent the number of legs each caterpillar has. Write an expression for the total number of legs that the caterpillar and Casey have together.

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Ответ:

0139236

16.03.2022

Mathematics

$\boxed{no \: \: \: solution}$

Step-by-step explanation:

$\frac{4x}{x - 3} = 7 + \frac{12}{x - 3} \\ \frac{4x}{x -3 } = \frac{7(x - 3)}{1(x - 3)} + \frac{12}{x - 3} \\ \frac{4x}{x - 3} = \frac{7x - 21 + 12}{x - 3} \\ \frac{4x}{x - 3} = \frac{7x - 9}{x - 3} \\\red{ use \: \: \: cross \: \: multipication} \\ 4x(x - 3) = (x - 3)(7x - 9) \\ 4 {x}^{2} - 12 = 7 {x}^{2} - 9x - 21x + 27 \\4 {x}^{2} - 12 = 7 {x}^{2} - 30x + 27$

So the answer has to be no solution

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