Chandra wants to estimate the percentage of people who smoke. She surveys 100 individuals and finds that 15 of them smoke. Find the margin of error for the confidence interval for the population proportion with a 98% confidence level.

M.E = 0.083

the margin of error for the confidence interval for the population proportion with a 98% confidence level is 0.083

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

p+/-M.E

Given that;

M.E = margin of error

Proportion p = 15/100 = 0.15

Number of samples n = 100

Confidence interval = 98%

z(at 98% confidence) = 2.33

Substituting the values we have;

0.15 +/- 2.33√(0.15(1-0.15)/100)

0.15 +/- 2.33√0.001275

0.15 +/- 2.33(0.035707142142)

0.15 +/- 0.083197641192

0.15 +/- 0.083

So;

p = 0.15

M.E = 0.083

the margin of error for the confidence interval for the population proportion with a 98% confidence level is 0.083

Part A. The slope of f(x) is 4. I observed that each time the y value would increase by 4 points every time the x value increases by 1. The slope of g(x) is 2. I identified the m value as it's in slope-intercept form. The slope of f(x) is greater then that of g(x) because 4>2

Part B. The y-intercept of f(x) is greater. It is given that when x is 0, y is -1, so the y intercept of f(x) is -1. Meanwhile, the y-intercept of g(x) is -7 after identifying the b value. -7<-1, concluding that f(x) has a greater y-intercept

Step-by-step explanation:

ty for the points