Choose the correct description of the graph of the compound inequality 3x + 1 > 10 and 4x less than or equal to 20 a number line with an open circle on 3, a closed circle on 5, and shading in between a number line with an open circle on 3, shading to the left, and a closed circle on 5, shading to the right a number line with a closed circle on 3, shading to the left, and an open circle on 5, and shading to the right a number line with a closed circle on 3, an open circle on 5, and shading in between

The graph is a number line with an open circle on 3, a closed circle on 5, and shading in between.

Step-by-step explanation:

We need to check the graph of the compound inequality:

       so on solving the first inequality

       3x>10-1 (on subtracting both side by 1)

        3x>9  

         x>3   ( on dividing both side by 3)

         Hence, we get a region on a number line from (3,∞).

           this inequality could also be written as:

             x≤5 ( dividing both side of the inequality with 5)

             Hence, we get a region on a number line from (-∞,5].

Hence, the intersection region from both the inequality is obtained as:

(3,∞)∩(-∞,5]=(3,5]

Hence,  The graph of this compound inequality is a number line with an open circle on 3, a closed circle on 5, and shading in between.

The  graphs are also attached to the answer.

Shania is correct.

Step-by-step explanation:

For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;

a/sin A = b/sinB

and

sin (angle) = opposite side/hypotenuse

cos (angle) = adjacent side/hypotenuse

tan (angle) = opposite/ adjacent

assuming a is the opposite side of angle A and b is also opposite of angle B

Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.

Hence, Shania is correct.