Christopher measured in line to be 7.2 inches long if the actual length of the line is 7.1 inches then what is the percent error of the measurement to the nearest 10th of a percent

1.4%

Step-by-step explanation:

To calculate the error, we first need to subtract Christopher measurement of the line by the actual length of the line to find the absolute error:

7.2 - 7.1 = 0.1

The absolute error is 0.1 inches.

Now, to know the percent error, we need to divide this value of error by the actual length of the line:

0.1 / 7.1 = 0.01408 = 1.408% = 1.4%

So the percent error of the measurement is 1.4%

The percent error in his measurement was 1.41%

Step-by-step explanation:

In order to compute the percentage error we first need to know the absolute error of his measurement. This error is given by what Christopher measured sutracted by the actual length, wich is:

absolute error = 7.2 - 7.1 = 0.1 inches

To know this value in percentage we need to know how many percentage 0.1 inches is from 7.1 inches. So we can use a rule of three such as 7.1 inches relates to 100% as 0.1 inches relates to x%. We have:

7.1 inches -> 100%

0.1 inches -> x

x = (100*0.1)/7.1 = 1.41 %

The percent error in his measurement was 1.41%

The correct answer is:

a) 25q + 10d + 5n + 60 = 187

Explanation:

One dollar and 87 cents can be written as 1.87.  However, since one dollar is equal to 100 cents, we can also write this as 187 cents.

Each quarter, represented by q, is equal to 25 cents; this gives us the expression 25q.

Each dime, represented by d, is equal to 10 cents; this gives us the expression 10d.

Each nickel, represented by n, is equal to 5 cents; this gives us the expression 5n.

We have 60 pennies.

This gives us the equation 25q+10d+5n+60=187.