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14.04.2021 •
Mathematics
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Indicate the equation of the given line in standard form.
The line that contains the point Q( 1, -2) and is parallel to the line whose equation is
y - 4 = 2/3 (x - 3)
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Ответ:
The equation of the line is;
3y = 2x-8
Step-by-step explanation:
Firstly, we need the to get the slope of the given line
To do this, we will write the equation of the line in the standard form
the standard form
is;
y = mx + b
where m is the slope and b is the y-intercept
y -4 = 2/3(x-3)
y -4 = 2x/3 - 2
y = 2x/3 -2 + 4
y = 2x/3 + 2
with respect to the given equation, the slope of the line is 2/3
Mathematically, when two lines are parallel, the slopes of the line are equal
So now, we want to find the equation of the line that has a slope of 2/3 and passes through the point (1,-2)
so;
y = 2x/3 + b
So substitute the values of (1,-2)
1 for x and -2 for y
-2 = 2/3(1) + b
-2 = 2/3 + b
b = -2 - 2/3
b = (-6-2)/3 = -8/3
So the equation of that line is;
y = 2/3x - 8/3
Multiply through by 3
3y = 2x - 8
Ответ: