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sonyav732
02.03.2021 •
Mathematics
Click on all the numbers that make the equation true. x = 9 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 4 5 6 7 8 9 10
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Ответ:
9514 1404 393
p(x) = (x+6)(x-3)(x-5)p(x) = (x-2)(x+2)(x^2 +36)p(x) = x^3 -7x^2 -x +7p(x) = x^4 -5x^2 -36Step-by-step explanation:
Each root r gives rise to a binomial factor (x-r). Each complex root also has a conjugate root, so roots ±ri give rise to a binomial factor (x^2 +r^2).
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1. p(x) = (x -(-6))(x -3)(x -5)
p(x) = (x+6)(x-3)(x-5)
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2. p(x) = (x -2)(x -(-2))(x^2 +6^2)
p(x) = (x -2)(x +2)(x^2 +36)
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If you want standard form, you can start with factored form, then multiply it out.
3. p(x) = (x -1)(x +1)(x -7) = (x^2 -1)(x -7) = (x^2 -1)x +(x^2 -1)(-7)
p(x) = x^3 -7x^2 -x +7
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4. p(x) = (x -3)(x +3)(x^2 +2^2) = (x^2 -9)(x^2 +4)
p(x) = x^4 -5x^2 -36