Click on the graph to choose the best match of the graphed quadratic equation. f(x) = x 2 + 4x

Direction: Opens Up

Vertex:  

(−2,−4)

Focus:

(−2, −15/4)

85° and 95°

Step-by-step explanation:

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)