Mathematics: Coin Toss A coin is tossed upward with an initial velocity of 32 feet per second from a height of 16 feet above the ground. The equation giving the object’s height h at any time t is h = 16 + 32t — 16tz Does the object ever reach a height of 32 feet?

Coin Toss A coin is tossed upward with an initial

leyslebravo7117

21.01.2022

The object ever reach a height of 32 feet in 1 second

Step-by-step explanation:

The equation giving the object’s height : h = 16 + 32t -16t^2

Where h = object’s height

t = time

We are supposed to find Does the object ever reach a height of 32 feet

Substitute h = 32 in equation

32 = 16 + 32t -16t^2

32-16= 32t -16t^2

16= 32t -16t^2

1=2t-t^2

t^2-2t+1=0

t^2-t-t+1=0

t(t-1)-(t-1)=0

(t-1)(t-1)=0

t=1,1

So, The object ever reach a height of 32 feet in 1 second

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natalieoppelt

27.02.2022

d= 2.80inch

Explanation:

Given:

Axial force= 30kip

d= 1inch

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

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