Complete the point slope equation of line through (1,-1) and (5,2) use exact numbers
)=

(1,-1)(5,2)
slope = (2 - (-1) / (5 - 1) = 3/4

there will be 2 point slope answers for this..
y - y1 = m(x - x1)
slope(m) = 3/4
(1,-1)...x1 = 1 and y1 = -1
sub
y - (-1) = 3/4(x - 1)
y + 1 = 3/4(x - 1) <=== this is one of them

y - y1 = m(x - x1)
slope(m) = 3/4
(5,2)...x1 = 5 and y1 = 2
sub
y - 2 = 3/4(x - 5) <== here is the other one 

The probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is 0.234375.

Step-by-step explanation:

Using the Minitab software for computing the desired probabilities.

We take n=6 and p=1/2  because we have six tosses and in binomial distribution the probability of success p remains constant in each trial whereas the probability of success in this case is getting heads.

When a coin is tossed then there are two possible outcomes head or tail.

So,

p= P(heads)=1/2=0.5  

The probability of getting zero heads in six tosses is computed by considering the following steps:

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=0 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

0    0.015625

So, the probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is computed by considering the following steps :

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=2 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

2    0.234375

So, the probability of getting exactly two heads in six tosses is 0.234375.