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Zykuko
07.10.2020 •
Mathematics
confidence interval of months to months has been found for the mean duration of imprisonment, , of political prisoners of a certain country with chronic PTSD.a. Determine the margin of error, E.b. Explain the meaning of E in this context in terms of the accuracy of the estimate.c. Find the sample size required to have a margin of error of months and a % confidence level. (Use months.)d. Find a % confidence interval for the mean duration of imprisonment, , if a sample of the size determined in part (c) has a mean of months.
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Ответ:
Complete Question
A 95% confidence interval of 19.3 months to 47.5 months has been found for the mean duration of? imprisonment, ??,of political prisoners of a certain country with chronic PTSD.
a. Determine the margin of error, E.
b. Explain the meaning of E in this context in terms of the accuracy of the estimate.
c. Find the sample size required to have a margin of error of 13 months and a 99% confidence level.? (Use 38 months. for standard deviation )
d. Find a 99% confidence interval for the mean duration of? imprisonment, ??, if a sample of the size determined in part? (c) has a mean of 36.5 months.
a
b
In this context E tell us that the true mean will lie within E = 14.1 of the sample mean
c
d
Step-by-step explanation:
Considering question a
From the question we are told that
The upper limit is U = 47.5 months
The lower limit is L = 19.3 months
Generally the margin of error is mathematically represented as
=>![E = \frac{ 47.5 - 19.3 }{2}](/tpl/images/0793/2805/809da.png)
=>![E = 14.1](/tpl/images/0793/2805/a46c5.png)
Considering question b
In this context E tell us that the true mean will lie within E = 14.1 of the sample mean
Considering question c
Generally the sample size is mathematically represented as
Here E is given as E = 13
Given that the confidence level is 99% then the level of significance is
=>![\alpha = 0.01](/tpl/images/0793/2805/877a5.png)
From the normal distribution table the critical value of
is
So
=>![n =57](/tpl/images/0793/2805/8f45b.png)
Considering question d
From the question
The sample mean is![\= x = 36.5](/tpl/images/0793/2805/edbc7.png)
Generally the margin of error is mathematically represented as
=>![E = 2.58 * \frac{38 }{57}](/tpl/images/0793/2805/9669f.png)
=>
Generally the 99% confidence interval for mean distribution is mathematically represented as
=>![23.514 < \mu < 49.486](/tpl/images/0793/2805/44e77.png)
Ответ:
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