amp1955
30.12.2020 •
Mathematics
Consider the ellipse (x^(2))/(16)+(y^(2))/(100)=1 .The tangent to this ellipse at (m,n) has x -intercept A=(a,0) and y- intercept B=(0,b) where a and b are positive. (a) Show that ab=(1600)/(mn) . (b) Use the relationship in part(a) and the fact that (m,n) lies on the ellipse to find the minimum value of ab .
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Ответ:
D. x = 4.
Step-by-step explanation:
As the 2 angles are congruent:
2.3x +25 = 5.8x + 11
2.3x - 5.8x = 11 - 25
-3.5x = -14
x = 14/3.5
x = 4.