Consider the equation 2(4x-5)=ax+b.from the list of digits provided, determine the values of a and b that make the solution to this equation x=3. (0 1 2 3 4) a=( ) b = ( ) the numbers in parentheses is u have to figure out which go in either a or b. ok

a=4, b=2

Step-by-step explanation:

Filling in the given information (x=3), your equation becomes ...

2(4·3 -5) = a·3 +b

2·7 = 3a +b

3a +b = 14

At this point, there are several ways you can proceed. One of them is to subtract possible b values from 14, and see which result(s) give an appropriate a-value.

3a = 14 -b

3a = 14 -{0, 1, 2, 3, 4}

3a = {14, 13, 12, 11, 10}

a = (14/3, 13/3, 4, 11/3, 10/3}

The only viable choice among the numbers offered is ...

a = 4, b = 2