Mathematics: Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

Consider the function below. f(x)= x^3 + 2x^2 -

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lanaasad7292

13.03.2022

Mathematics

In the Figure below is shown the graph of this function. We have the following function:

f(x)=x^3+2x^2-x-2

The y-intercept occurs when x=0 , so:

f(0)=(0)^3+2(0)^2-(0)-2=-2

Therefore, the y-intercept is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three x-intercepts :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the x-intercepts occur when y=0 . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$

Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

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Ответ:

levicorey846

24.07.2022

Mathematics

Place the compass on a point on the original line.

Step-by-step explanation:

If the compass is placed on the original line point, then is will be the exact same spot and angle for the other line. They should met and form a right angle .

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Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

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