Consider the line - 8x-5y = -7. What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?

See below

Step-by-step explanation:

First, you need to find the slope of the given line.  You can do this by rearranging the equation so that it is  in slope-intercept form (y = mx + b).

-8x - 5y = -7

-5y = 8x - 7

y = -8/5x + 7/5

The slope of this line is -8/5.  

The slope of a line that is perpendicular will be the negative reciprocal.  You have to change the sign, and basically flip the numerator upside down.  The slope of the perpendicular line will be 5/8

-8/5 = 8/5 = 5/8

The slope of a line that is parallel will be equal.  This means that the slope will be -8/5.

Step-by-step explanation:

Part 1: 110110two to base ten

For conversion from base 2 to base 10 we multiply each digits of given number with powers of 2

So

So 110110two when converted in base 10 will be equal to 54

Part 2: 25ten to base two

For conversion from base 10 to base 2 we will divide the given number with 2 repeatedly and store the remainders until the quotient comes 1. The solution is as follows:

25/2 = 12     remainder 1

12/2 = 6       remainder 0

6/2 = 3        remainder 0

3/2 = 1         remainder 1

Now the remainders will be written in inverse order as:

=1001 base 2

So 25 in base 10 is equal to 1001 base 2

I hope it will help you!