Consider the line y=-2/7x-7 and the point is (-7,-4) what would the perpendicular line be and the parallel be

a) The equation of line perpendicular to above line and passes through point (-7,-4) is

b) The equation of line parallel to above line and passes through point (-7,-4) is

Step-by-step explanation:

We are given the line:

The slope of the above equation is: (By comparing with general form where m is slope)

a) Find equation of line perpendicular to above line and passes through point (-7,-4)

If two lines are perpendicular there slopes are opposite reciprocal i.e

The slope of new line will be:

Now finding y-intercept using slope and point (-7,-4)

So, the equation of line perpendicular to above line and passes through point (-7,-4) will be:

So, the equation of line perpendicular to above line and passes through point (-7,-4) is

b) Find equation of line parallel to above line and passes through point (-7,-4)

If two lines are parallel there slopes are same i.e

The slope of new line will be:

Now finding y-intercept using slope and point (-7,-4)

So, the equation of line parallel to above line and passes through point (-7,-4) will be:

So, the equation of line parallel to above line and passes through point (-7,-4) is

Option A.

Step-by-step explanation:

Based on the information given in the problem, you can draw the figure shown attached.

The area of  rectangle can be calculated with the following formula:

Where l is the length and w is the width.

As you can see in the figure:

- The width is:

-The length is:

Therefore, you must multiply both expressions to obtain the area:

Add like terms:

Then, the function that represents the area of the cake is: