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naomicervero
07.05.2020 •
Mathematics
Construct a 90% confidence interval of the population proportion using the given information.
X= 175
n= 250
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Ответ:
The 90% confidence interval of the population proportion is (0.6523, 0.7477).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 90% confidence interval of the population proportion is (0.6523, 0.7477).
Ответ:
Tbe confidence interval marked the range of values for which the true population mean is estimated to be given a certain level of confidence. Hence, the confidence interval is (0.6523, 0.7477)
Since the sample size is large enough, we use the the Z distributuon :
Confidence interval is defined thus :
Mean ± margin of errorMargin of Error :
Hence,
Margin of Error =Lower confidence boundary = 0.7 - 0.0290 = 0.6523
Upper confidence boundary = 0.7 + 0.0290 = 0.7477
Therefore, the confidence interval is (0.6523, 0.7477)
Learn more : link
Ответ:
Surface Area of the cylinder is
Or 87.92 square units.
Step-by-step explanation:
Given:
radius
= 2
height
= 5
We need to find the surface area of the cylinder.
Solution:
Now we can say that;
Surface Area of the cylinder is given by the formula.
Now Substituting the given values we get;
Hence Surface Area of the cylinder is
Or 87.92 square units.