Mathematics: Cos 12 in terms of sinea.)sin 78b.)sin 62c.)sin 38d.)sin 81

Cos 12 in terms of sinea.)sin 78b.)sin 62c.)sin

Ответ:

stricklandashley43

27.06.2022

Mathematics

$\dfrac{1}{2} \pm \dfrac{\sqrt{21}}{6}$

Step-by-step explanation:

6x^2 - 6x - 2 = 0

Divide both sides by 2.

3x^2 - 3x - 1 = 0

We compare it to the standard form:

ax^2 + bx + c = 0

We have a = 3, b = -3, c = -1.

To factor, we need two numbers that multiply to ac and add to b.

ac = 3 * (-1) = -3

-3 = -3 * 1; -3 + 1 = -2

-3 = -1 * 3; -1 + 3 = 2

There are no two integers whose product is -3 and whose sum is -3, so we cannot factor the trinomial. We use the quadratic formula to solve the equation.

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(3)(-1)}}{2(3)}$

$x = \dfrac{3 \pm \sqrt{9 + 12}}{6}$

$x = \dfrac{3 \pm \sqrt{21}}{6}$

$x = \dfrac{1}{2} \pm \dfrac{\sqrt{21}}{6}$

0,0(0 оценок)

Cos 12 in terms of sine
a.)sin 78
b.)sin 62
c.)sin 38
d.)sin 81

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question