Could someone me with this problem

See the explanation.

Step-by-step explanation:

Given  CB║ED And CB≅ED

Since it is given that CB≅ED

The ΔDEF is a reflection of ΔCBE along point 'E'

So, the point 'E' is center of reflection.

And we know under point reflection the images do not change size and shape.

So the sides of both triangles are same, angle will be the same.

Here we can see ∠DEF = ∠BCF  and ∠EDF=∠CBF  also CB=ED

Then ΔDEF≅BCE