ceeejay0621
10.02.2021 •
Mathematics
Create a polynomial in the form ax^3+bx^2+cx=0 that has solutions of x=0,x=-5 and x=11, where a=3
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Ответ:
a
Step-by-step explanation:
a
Ответ:
Since we are given the solutions, we can rewrite them.
x=-5 is (x+5)
x=11 is (x-11)
x=0 is just x
Now we can write our equation:
3x(x+5)(x-11)=0
*3 comes from the a being 3
Now we multiply, I’d recommend starting by using FOIL on the last two first and getting;
3x(x^2-6x-55)
Then distribute the 3x:
3x^3-18x^2-165x
Ответ:
A) If the equation of the line is y = mx + c, then, m is the slope and c is the y-intercept.
Therefore, in the given equation y = 5x + 10, slope is 5 and y-intercept is 10.
B) 5 is the rate of change. To obtain the initial amount, put x = 0.
y = 5(0) + 10
y = 10
So, the initial amount is 10. Rate of change is the number of baskets of berries picked each hour and the initial amount is the number of baskets of berries available before the workers picked.
C) If we substitute x = 0, then y = 10. If we put y = 0, then x = - 2. Please find the graph attached.