CoolxBreeze
25.09.2020 •
Mathematics
Customers at Costco spend an average of $130 per trip (The Wall Street Journal, October 6, 2010). One of Costco's rivals would like to determine whether its customers spend more per trip. A survey of the receipts of 25 customers found that the sample mean was $135.25. Assume that the population standard deviation is $10.50 and that spending follows a normal distribution. Use standard normal curve area table.A, Specify the appropriate null and alternative hypotheses to test whether average spending at the rival�s store is more than $130.B. Calculate the value of the test statistic.C. Calculate the p-value.D. Calculate the critical value
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Ответ:
Step-by-step explanation:
Given the following :
Average amount spent (U) = $130 per trip
Sample size (n) = 25
Sample mean (m) = $135.25
Population standard deviation (sd) = $10.50
Assume a standard distribution.
A.) Null hypothesis ; Alternative hypothesis
Hnull : U ≤ 130 ; Ha : U > 130
B.) value of test statistic :
Z = (m - U) / standard error
Standard Error = sd / sqrt(n)
Standard Error( S.E)= 10.50 / sqrt(25)
S.E = 10.50 / 5 = 2.1
Hence,
Z = (135.25 - 130) / 2.1
Z = 5.25 / 2.1
Z = 2.5
C. Calculate the p-value.
Using the p value calculator by entering the z-score above, the p value obtained is 0.0124
P value = 0.01
D. Calculate the critical value
Ответ:
aww thank you
*gives you a cake*
thank you for the points