D(1) = 3
d(n) = d(n = 1) - 14
find the 3rd term in the sequence.

- 25

Step-by-step explanation:

Given

d(n) = d(n - 1) - 14 with d(1) = 3, then

d(2) = d(1) - 14 = 3 - 14 = - 11

d(3) = d(2) - 14 = - 11 - 14 = - 25 ← third term

LN=37 units

Step-by-step explanation:

In this problem I will assume that M is a point between point L and point N

therefore

LN=LM+MN

substitute the given values

LN=22+15=37 units