D^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 a. d^2+14d+16/(d+8)(d-8) b. 2d^2+14d+16/(d+8)(d-8) c.2d^2+15d+18/2d^2+d-88 d.2d^2+15d+18/(d+8)(d-8)

option B.

   2d^2  + 14d + 16        
----------------------------
        (d+8)(d-8)              

Explanation:

The question is:



1) Start factoring all the polynomials to rewrite the fractions.

2) d^2 + d - 30 = (d + 6)(d - 6)

3) d^2 + 3d - 40 = (d + 8)(d - 5)

4) d^2 + 14d + 48 = (d + 6) (d + 8)

5) d^2 - 2d - 48 = (d - 8)(d + 6)

6) rewrite the fractions:

  (d+6)(d-5)         (d+8)(d+6)
----------------- +  -----------------
  (d+8)(d-5)          (d-8)(d+6)

7) simplify the fractions cancelling the factors that are equal in the numerator and the denominator:

  d+6       d+8
-------- + -------
  d+8       d-8

8) take least common denominatior: (d+8)(d-8), and sum the fractions:

   (d-8)(d+6) + (d+8)^2
--------------------------------
          (d+8)(d-8)

9) expand the parenthesis in the numerator and combine like terms:

 d^2 - 2d - 48 + d^2 + 16d + 64
------------------------------------------- =
               (d+8)(d-8)

        2d^2  + 14d + 16        
=   ----------------------------
              (d+8)(d-8)              

And that is the option B.

Option D is correct.

The system of inequalities are:

;

Step-by-step explanation:

Let h represents the number of hamburgers and c represents the number of cheeseburgers.

From the given statement:

Each hamburgers sells for $3 each

then,

the total sales of hamburgers sells is 3h

Each cheeseburgers sells for $3.50 each

then,

the total sales of cheeseburgers sells is 3.50c

Since, he has 100 burgers

then the inequality :

And also, he must sell to have sales of at least $ 80

at least represented by symbol  

then the inequality is;

Therefore, the system of inequality:

;