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stipton05
03.02.2020 •
Mathematics
David measured the distance from his house to a soccer field as 3 km. the actual distance from his house to the soccer field is 2.84 km.
solve for the approximate percent error in david’s measurement. round to the nearest tenth of a percent, if necessary. a. 0.16% b. 5.3% c. 5.6% d. 16%
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Ответ:
(error/actual value) x 100
= [(3-2.84)/2.84] x 100
= 5.6%
The answer is C
Ответ: