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92054ggg
92054ggg
12.11.2019 • 
Mathematics

Davide wants to find the zeros of the polynomial p(x)=x3−2x2−9x+18. his work is shown below.

step 1: p(x)=(x+3)(x−3)(x−2)
step 2: x+3=0
x−3=0x−2=0
step 3: x=2, x=3, x=−3

explain why davide’s work shows that 2, 3, and −3 are zeros of p(x) by matching each step with the appropriate justification.

step 1:
step 2:
step 3:

(a) davide solves for x in each of the equations from step 2. the zeros of a polynomial are the x -values for which p(x)=0 .
(b) davide gets rid of the x in each of the equations from step 2 by setting x=0 . the zeros of a polynomial occur when x=0 .
(c) davide factors the polynomial p(x) into linear factors using factoring by grouping and the difference of squares.
(d) davide factors the polynomial p(x) into linear factors using the difference of cubes method.
(e) davide sets each linear factor equal to 0 because the x -value for the zero of a polynomial is 0 .
(f) davide sets each linear factor equal to 0 because of the zero product property.

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