Demonstrate, using your own unique example, how to divide a segment by a given ratio. be sure to provide coordinates and a ratio that does not have a numerator or denominator of 1. if some one could me out that would be awesome. need this urgently.

Say for example we have segment A with endpoints coordinates of (a,b) and (x,y) and we wish to divide the segment into parts. The ratio of division is assumed to be r. In this case, we identify the first coordinates of the segment next to (a,b) by:

(c,d) = ((x-a)/r + a  , (y-b)/r + b) 

This formula is used including the constant portion of the division of the segment, (x-a)/r. The addition, a, can vary depending on the position of the coordinates to be taken. On the other end, before (x,y), the coordinates should be 

(v,w) = (y - (x-a)/r , z - (y-b)/r )

Hope it is right can i get a crown if this helped please

Direct variation in mathematics is when two numbers are written in an equation where one of the numbers multiplied by a constant term to equal the other. 

In the table in the equation, we see direct variation.

X    Y
1     7
2     14
3     21
4     28

We can find the constant of the variation by dividing y by x. This constant should remain the same for all terms of x in the table with their corresponding y values.

y/x
7/1=7
14/2=7
21/3=7
28/4=7

As we can see, the values in the table all share a direct variation between x and y with the value 7.

This can be expressed in an equation: y = 7x.