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golderhadashaowtatz
17.07.2020 •
Mathematics
Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. f(x) = −one half(x − 6)2 + three halves f(x) = one half(x − 6)2 + three halves f(x) = −one half(x + three halves)2 + 6 f(x) = one half(x + three halves)2 + 6
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Ответ:
A parabola is a plane that is approximately U-shaped.
The equation of the parabola is:![\mathbf{y = \frac{1}{2}(x - 6)^2 + \frac 32}](/tpl/images/0708/4809/13cda.png)
The given parameters are:
First, equate the directrix to 0
The equation is then calculated as:
Where:
So, we have:
Expand
Subtract y^2 from both sides
Collect like terms
Divide through by 2
Express 39 as 36 + 3
Factor out 3/2
Expand the bracket
Factorize
Factor out x - 6
Express as squares
Hence, the equation of the parabola is:![\mathbf{y = \frac{1}{2}(x - 6)^2 + \frac 32}](/tpl/images/0708/4809/13cda.png)
Read more about equations of parabola at:
link
Ответ:
Second choice.
f(x) = 1/2(x - 6)^2 + 3/2.
Step-by-step explanation:
The distance of a point (x, y) from the focus = the distance of the point from the directrix, so:
(x - 6)^2 + (y - 2)^2 = (y - 1)^2
x^2 - 12x + 36 + y^2 - 4y + 4 = y^2 - 2y + 1
x^2 -12x + 39 = 2y
y = f(x) = 1/2 (x^2 - 12x + 39)
I see you want the answer in vertex for so it is:
f(x) = 1/2 [ (x - 6)^2 - 36) + 39)
f(x) = 1/2(x - 6)^2 + 3)
f(x) = 1/2(x - 6)^2 + 3/2.
Ответ:
1. y = 12x2 - 9x + 4 has no real solution(s).
2. 10x + y = -x2 + 2 has two real solution(s).
3. 4y - 7 = 5x2 - x + 2 + 3y has no real solution(s).
4. y = (-x + 4)2 has one real solution(s).