Mathematics: :) describe the nature of the roots for this equation. 3x^2+x-5=0 a. two complex roots b. two real, rational roots c. one real, double root d. two real, irrational roots

:) describe the nature of the roots for this equation.

Ответ:

edsimms21111

30.12.2021

$3x^2+x-5=0 \\ \\
a=3 \\ b=1 \\ c=-5 \\ \Delta=b^2-4ac=1^2-4 \times 3 \times (-5)=1+60=61$

The discriminant Δ is greater than 0, so there are two real roots.

$x=\frac{-b \pm \sqrt{\Delta}}{2a}=\frac{-1 \pm \sqrt{61}}{2 \times 3}=\frac{-1 \pm \sqrt{61}}{6}$

√61 is an irrational number, so both roots will be irrational.

The answer is D.

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Ответ:

bananaslada

20.08.2020

Mathematics

Around 14.6 feet per second or so.

Step-by-step explanation:

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:) describe the nature of the roots for this equation. 3x^2+x-5=0
a. two complex roots
b. two real, rational roots
c. one real, double root
d. two real, irrational roots

Ответ:

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