Determine an equation of the line that passes through the point (-2, 3) and is perpendicular to the line whose equation is−2x+y−2 =0. Then draw both lines on the same pair of axes.

Since the line passes through  (−2,3)  we can plug it in the equation to find out the value of  C  

2(−2)−3−2+C=0⟹C=9  

So the equation is

2x−y−2+9=0  

or

2x−y+7=0

Step-by-step explanation:

Common Sense...

C. x=1 or x=-5

Step-by-step explanation:

1. First, we have to get the absolute value alone.

2|x+2|-1=5

2. Add 1 to both sides.

2|x+2|-1 +1 = 5 +1. The -1 and +1 will cancel each other out.

You will get 2|x+2|=6.

3. Divide 2 by both sides.

=

The division of 2 and the multiplication of 2 on the side of the absolute value will also cancel each other out.

You will get |x+2|=3.

4. Next, we will split this absolute value equation into two equations because we don't know if the variable of x that's inside of the absolute value is negative or not.

x+2=3 or x+2=-3.

5. Subtract 2 from all sides.

x+2 -2 =3 or x+2 -2 =-3

You will get x=1 or x=-5.

x=1 or x=-5 is your final answer.