miami158999
15.03.2020 •
Mathematics
Determine and state an equation of the line perpendicular to 5x-4y=10nand passing through point (5,12).
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Ответ:
The equation of line perpendicular to and passing through the point (5,12) is
The line given in the problem is in Standard Form. The standard form of a linear equation is:
Where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1.
The slope of an equation in standard form is: . Substituting the values from the equation in the problem gives:
Let's call the slope of the line perpendicular to this line . The slope of a perpendicular line is:
We can now use the point-slope formula to find the equation of the line. The point-slope formula states:
Therefore, the equation of line perpendicular to and passing through the point (5,12) is
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Ответ:
4x + 5y = 80
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 5x - 4y = 10 into this form
Subtract 5x from both sides
- 4y = - 5x + 10 ( divide all terms by - 4 )
y = x + ← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= - = - = - , thus
y = - x + c ← is the partial equation
To find c substitute (5, 12) into the partial equation
12 = - 4 + c ⇒ c = 12 + 4 = 16
y = - x + 16 ← in slope- intercept form
Multiply through by 5
5y = - 4x + 80 ( add 4x to both sides )
4x + 5y = 80 ← in standard form
Ответ:
The two angles are complementary so 3x-36+2x+26=180
Just simplify from there.