![wisal96](/avatars/28402.jpg)
wisal96
15.08.2020 •
Mathematics
Determine the sample size required to estimate the mean score on a standardized test within 4 points of the true mean with 98% confidence. Assume that s = 14 based on earlier studies.
Solved
Show answers
More tips
- F Food and Cooking Discover the Benefits and Properties of Dates...
- C Computers and Internet Dynamically Assigned IP Address: What Is It and How Does It Work?...
- H Health and Medicine Angina: Causes, Symptoms, and Treatment...
- C Computers and Internet How to Learn to Type Fast?...
- F Food and Cooking Delight for Gourmets: How to Prepare Liver Pate...
- S Style and Beauty How to braid friendship bracelets?...
- H Health and Medicine Mercury Thermometer Danger: What to do when a thermometer breaks?...
- F Food and Cooking Which Calamari Salad is the Most Delicious?...
- S Society and Politics 10 Tips for Boosting Your Self-Esteem...
- F Food and Cooking The Most Delicious and Simple Fish in Batter Recipe...
Answers on questions: Mathematics
- M Mathematics Using the laws of exponents, demonstrate and explain why 10^1/2 = 100^1/4...
- M Mathematics Pls help I need a good grade...
- M Mathematics Jared can clear his driveway of snow in 36 minutes. It takes his brother 48 minutes. To the nearest minute, how long does it take to clear the driveway if they work...
- M Mathematics What is the value of x A.6 B. 10 C.4 D.8...
- M Mathematics Someone help me on this...
- M Mathematics Determine the domain and range of the function below: ...
- M Mathematics BILLIE EYELASH IS QUEEN REEEEEEEE...
- M Mathematics Choose a number sentence is that illustrates distribute property of multiplication over addition 2×7+8 = 2+7×2+8...
- M Mathematics In the diagram below of parallelogram ABCD, line segments AC, BD, and FG all intersect at E. Prove that △AEF ≅ △CEG....
- M Mathematics How do you write 6.69x10^-4 in standard form?...
Ответ:
Sample size required to estimate the mean score on a standardized test is 67.
The confidence level (C) = 98% = 0.98
α = 1 - C = 0.02
α/2 = 0.02/2 = 0.01
The z score of α/2 is the same as the z score of 0.49 (0.50 - 0.01) which is equal to 2.33
Given that:
Standard deviation (σ) = 14, margin of error (E) = 4, n = sample size, hence:
Hence the sample size required to estimate the mean score on a standardized test is 67.
Find out more at: link
Ответ:
67
Step-by-step explanation:
Formula to calculate sample size:
, where s = standard deviation on prior studies , z* = two tailed critical value for confidence level , E = margin of error
Given: E = 4 , s= 14 and confidence level = 98%
Z-value for 98% confidence = 2.326
Then, required sample size:![n=(\dfrac{2.326\times 14}{4})^2=(8.141)^2=66.275881\approx67](/tpl/images/0722/7919/a0106.png)
Hence, the required sample size = 67 .
Ответ:
The rate of change is the slope (rise/run, y/x). To find that, we use the equation (y2-y1) over (x2-x1). It means take the second "y" and subtract it from the first "y" and the same to "x". If I plug in the numbers, it would be (3-6) over (5-4), and after you subtract, the answer simplifies to: -3/ 1 which is -3. Yay! We got the slope (rate of change) done.
Now let's find the y-intercept by using the formula of point-slope form,
y-y1= m (slope) (x-x1). This is saying you "y" is subtracted from the first
"y" of the points which equals the slope (m) times the quantity of "x" subtracted by the first "x" of the points.
Let's plug the numbers in: y-6 = -3 (x-4). Let's distribute -3 to the parenthesis, and after that it should simplify to: y-6 = -3x + 12. To get "y" by itself, add 6 to both sides: y = -3x +18. We have finally found the slope-intercept equation for those two points (4,6) and (5,3). To then find the y-intercept in this equation, it would be the 18, because -3 is the slope, so that makes 18 the y-intercept.
In conclusion, the rate of change is -3 and the y-intercept is 18.
I hope this helps!
May