Determine the standard form of an equation that passes through (2,2) and (-6,4).
a) x+4y=10
b) y=-1/4x+5/2
c) -x+y=5/2
d) 2x+2y=-24

n = sqrt(7) - 5 or n = -5 - sqrt(7)

Step-by-step explanation:

Solve for n:

(n^2 + 10 n + 18)/(n + 5) = 0

Multiply both sides by n + 5:

n^2 + 10 n + 18 = 0

Subtract 18 from both sides:

n^2 + 10 n = -18

Add 25 to both sides:

n^2 + 10 n + 25 = 7

Write the left hand side as a square:

(n + 5)^2 = 7

Take the square root of both sides:

n + 5 = sqrt(7) or n + 5 = -sqrt(7)

Subtract 5 from both sides:

n = sqrt(7) - 5 or n + 5 = -sqrt(7)

Subtract 5 from both sides:

 n = sqrt(7) - 5 or n = -5 - sqrt(7)