Determine whether the following argument is valid. If the argument is correct, what rule of inference is being used? If it is not, what logical error occurs? If n is a real number with n > 2, then n^2n 2 > 4. Suppose that n ≤ 2. Then n^2n 2 ≤ 4.

  3.27 meters

Step-by-step explanation:

The given equation gives a y(0) = 0, for the deflection of 3 cm. Then for a deflection of 2.5 cm, we want y(x) = 0.005, half a centimeter above the low point on the beam. Using this value, we can solve for x:

  0.005 = 3/6400x^2

  32/3 = x^2

  4√(2/3) = x ≈ 3.26599 ≈ 3.27 . . . . meters

The deflection of the beam is 2.5 cm at a distance of 3.27 meters from center.