Destinirainer
27.01.2020 •
Mathematics
Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 4x - 5y = 24 2x + 3y = -10 one and only one solution infinitely many solutions no solution find the solution, if one exists. (if there are infinitely many solutions, express x and y in terms of the parameter t. if there is no solution, enter no solution.)
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Ответ:
it has one and only one solution.
Step-by-step explanation:
The given system of equations is expressed as
4x - 5y = 24 - - - - - - - - - - - - -1
2x + 3y = -10 - - - - - - - - - - - - - 2
We would eliminate x by multiplying equation 1 by 1 and equation 2 by 2. It becomes
4x - 5y = 24
4x + 6y = - 20
Subtracting, it becomes
- 11y = 44
Dividing the left hand side and the right hand side of the equation by
- 11, it becomes
- 11y/- 11 = 44/- 11
y = - 4
Substituting y = - 4 into equation 2, it becomes
2x + 3 × - 4 = -10
2x - 12 = - 10
2x = - 10 + 12
2x = 2
Dividing the left hand side and the right hand side of the equation by
2, it becomes
2x/2 = 2/2
x = 1
Ответ: