Device uses five silicon chips. Suppose the five

Ответ:

china236

18.01.2022

76.96% probability of no defective chips.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The combinations formula is important to solve this question.

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

Sample of 100 chips, of which 5 are defective and 100-5 = 95 are not defective.

We want to find the probability that there are no defective chips.

So this is a combination of 5 from a set of 95.

$D = C_{95,5} = \frac{95!}{5!(95-5)!} = 57940519$

Total outcomes:

Combination of 5 from a set of 100.

$T = C_{100,5} = \frac{100!}{5!(100-5)!} = 75287520$

Probability:

$P = \frac{D}{T} = \frac{57940519}{75287520} = 0.7696$

76.96% probability of no defective chips.

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kony345p

16.04.2020

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Step-by-step explanation:

Basically you have to divide the number given, and the single ratio. The multiply this by the first number in the single ratio.

Hope this helped! Took a while

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