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babygirl1780
19.02.2021 •
Mathematics
Different dealers may sell the same car for different prices. The sale prices for a particular car are normally distributed with a mean and standard deviation of 26 2626 thousand dollars and 2 22 thousand dollars, respectively. Suppose we select one of these cars at random. Let X = X=X, equals the sale price (in thousands of dollars) for the selected car.
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Ответ:
Complete question :
Different dealers may sell the same car for different prices. The sale prices for a particular car are normally distributed with a mean and standard deviation of 26 thousand dollars and 2 thousand dollars, respectively. Suppose we select one of these cars at random. Let X represent the sale price (in thousands of dollars) for the selected car.1. Find P(26< X<30) You may round your answer to two decimal places
0.48
Step-by-step explanation:
Mean, m = 26000 ; Standard deviation, s = 2000
P(x < x)
Zscore = (x - m) / s
P(26< X<30) ;
P[(26 - 26 / 2) < (30 - 26) / 2)]
P[(0 < Z < 2)]
P(Z < 2) - P(Z <0)
Using a z table of z calculator, we can obtain the probabilties of the Z value :
0.97725 - 0.5
= 0.47725
= 0.48 ( 2 decimal places)
Ответ:
holy smokes europa2433 stop deleting my answer I'm gonna go broke!!!
Step-by-step explanation: