Do question 4 and explain how you got the answer . the question is on the image

Step 1: Subtract 50 from both sides.
y+50−50=200−50y=150

y=150

x+2y=200
x=y+50 
if x + 2y = 200, then let's solve it for x... 
x = 200 - 2y (subtracted 2y from both sides) 
Now we have two "x +" equations" 
x = y + 50
x = 200 - 2y 
If x equals two things, those two things equal each other (transitive property) 
y + 50 = 200 - 2y 
3y + 50 = 200 (added 2y to both sides) 

3y = 150 (subtracted 50 from both sides) 
y = 50. 
if y = 50, sub 50 back in for y into either of the two original equations (how about both to check?) 
x + 2(50) = 200
x + 100 = 200
x = 100 
x = 50 + 50
x = 100 
it's the same, so x = 100, y = 50
The lines cross at (100, 50)
hopes this helps :) :D :)

See explanation below.

Step-by-step explanation:

Part A:

(i). They both correct because they could have a third degree polynomial that crosses the x-axis 3 times.

(ii). To find the zero's of the first one, set function equal to zero and use zero factor principle given as:

So, we have: