Does anyone have the answers for the the first semester honors geometry Cumulative exam on edge unity?

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anggar20

18.01.2020

Mathematics

The integer b for $\rm b\sqrt{2}$ such as $\rm \sqrt{3}\times \sqrt{6} = b\sqrt{2}$ holds good is 3 .

According to the property of square root for any positive integer x

$\rm \sqrt{x} \times \sqrt{x} = x....(1)$

According to the given condition

$\rm \sqrt{3}\times \sqrt{6} = b\sqrt{2}$

We can simplify the left hand side of the equation as follows

$\sqrt{3}\times \sqrt{6}$

$= \sqrt{3}\times \sqrt{2\times 3 }$

$= 3\sqrt{2}$ ( By using equation (1))

So on comparing with right hand side of equation (1) we get

$\rm 3\sqrt{2} = b\sqrt{2}\\hence \; on\; comparing\\b = 3$

The integer b for $\rm b\sqrt{2}$ such as $\rm \sqrt{3}\times \sqrt{6} = b\sqrt{2}$ holds good is 3 .

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