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vieraml58
15.01.2021 •
Mathematics
Donnie is considering two different DVD rental
stores, both of which have a one-time membership
fee and a fee per rented DVD,
The cost for renting DVDs at the first store is shown
below:
Number of
DVDs rented
Cost (5)
1
5.50
2
7.00
3
8.50
The cost for renting DVDs at the second store is
modeled by the linear function c = 5+ 2d where dis
the number of DVDs rented and c is the cost.
Part A: Which store charges more for each DVD rented? Explain in words how you know
Part:b Which store charges a higher membership fee to begin renting DVD's. Explain in words how know,
Part : Which store charges more for renting 6 DVD'S? Show your work
Solved
Show answers
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Ответ:
Option 1 - StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.
Step-by-step explanation:
Given : Expression "six less than the quotient of a number and two, increased by ten".
To find : What is the expression and value of expression when n = 8?
Solution :
Let the number be 'n'.
The quotient of a number and two i.e.![\frac{n}{2}](/tpl/images/0515/8586/cabdc.png)
Six less than the quotient of a number and two i.e.![\frac{n}{2}-6](/tpl/images/0515/8586/297e5.png)
Six less than the quotient of a number and two, increased by ten i.e.![\frac{n}{2}-6+10](/tpl/images/0515/8586/2bf63.png)
The required expression is
.
Now, when n=8,
The value of the expression is 8.
Therefore, option 1 is correct.
StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.