Draw a line segment of length 8 cm divide it in the ratio 5:3

pl hel

Draw the line segment AB = 7 cm.

Draw ray BX making an acute ∠ABX.

Along BX. mark off five points B1, B2, B3, B4 and B5. Join B2 to A.

Through B5 draw B5P || B2A, intersecting BA produced at P.

The point P so obtained is the required point which divides AB externally in the ratio 3:5.

Thanks for the points <33

Step-by-step explanation:

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