ducational Television In a random sample of people, said that they watched educational television. Find the confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

Complete Question

Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

The 90% confidence interval is        

Step-by-step explanation:

From the question we are told that

     The sample size is  n = 200

     The number of people that watched the educational television is

Generally the sample proportion is mathematically represented as

=>              

From the question we are told the confidence level is  90% , hence the level of significance is    

=>  

Generally from the normal distribution table the critical value  of   is  

Generally the margin of error is mathematically represented as  

=>    

=>    

Generally 95% confidence interval is mathematically represented as  

=>    

=>          

x^2 − 5x − 2 = 0.

a = 1

b = -5

c = -2

x = (5 +- sqrt(25 +8)) / 2

x1 = 5.3723

x2 = -0.37228

Step-by-step explanation: