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Izzyfizzy1
30.06.2021 •
Mathematics
During the kickoff at a local high school football game, a football is placed onto a tee to a height of 0.125 feet above the ground. The football is kicked with an initial velocity of 80 feet per second. If the ball is caught at a height of 5 ft, approximately how long did it remain in the air? Round to the nearest hundredth of a second. Answer the question and make an equation
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Ответ:
Time in air is 7.5 s.
Step-by-step explanation:
initial height, h = 0.125 feet
initial velocity, u = 80 ft/s
final height, h' = 5 ft
acceleration due to gravity, g = 32 ft/s^2
Let the time is t to reach the maximum height.
v = u - gt
0 = 80 - 32 t
t = 2.5 s
Let the time is t' from top to ground.
So the tie is 5 s
The time in air is
T = 2.5 + 5 = 7.5 s
Ответ:
You get this answer by adding the two together because mWEV is equivalent to the two known angles put together.
Hope this helps!