![tatianaware1617](/avatars/39.jpg)
tatianaware1617
27.09.2019 •
Mathematics
Eight and one sixth minus 3 and five sixth
Solved
Show answers
More tips
- F Food and Cooking The Disease That Haunted Abraham Lincoln...
- P Philosophy What is Something for you?...
- S Style and Beauty Intimate Haircut: The Reasons, Popularity, and Risks...
- A Art and Culture When Will Eurovision 2011 Take Place?...
- S Style and Beauty How to Choose the Perfect Hair Straightener?...
- F Family and Home Why Having Pets at Home is Good for Your Health...
- H Health and Medicine How to perform artificial respiration?...
- H Health and Medicine 10 Tips for Avoiding Vitamin Deficiency...
- F Food and Cooking How to Properly Cook Buckwheat?...
- F Food and Cooking How Many Grams Are In a Tablespoon?...
Answers on questions: Mathematics
- E English At times, Hester wonders if pearl is what? A. A perfect angel from God B. An imp of evil...
- M Mathematics In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch....
- M Mathematics Aseafood restaurant claims an increase of $1,750.00 over its average profit during a week where it introduced a special of baked clams a.if this is true,how much...
Ответ:
First do the whole number: 8 - 3= 5
1 5 4 2
-- -- -- = -- = --
6 6 6 3
5 and 4/6th Simplify 5 and 2/3rds
Ответ:
the distance from point C to D is 7.75m
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo
A vertical flagpole, AB,has a height of 46m. The points B, C and D lie on level ground, and BCD is a straight line Point C is 21 m from the base of the flagpole. The angle of elevation of the top of the flagpole from point D is 58 degrees
How far apart are points C and D?
My
Given the infomation:
AB: 46mBCD is a straight lineBC = 21mIn triangle ABD, with angle of elevation from D to top of flag pole is 58 degrees.
<=>![\tan \theta =\frac{perpendicular}{base}](/tpl/images/0644/1135/f56df.png)
<=> tan(58) =![\frac{AB}{BD}](/tpl/images/0644/1135/9bcc1.png)
<=> BD =![\frac{AB}{tan(58)}](/tpl/images/0644/1135/af822.png)
<=> BD =![\frac{46}{1.6}](/tpl/images/0644/1135/a90cd.png)
<=> BD = 28.75
From the figure:
BD = BC + CD
<=> CD = BD - BC
<=> CD = 28.75 - 21 = 7.75m
So the distance from point C to D is 7.75m