Elena’s father puts $460 into savings account for her.the pays 2.5% simple interest each year.if he neither adds nor withdraws money from the account,how much interest will the account earn after 4years?
round to the nearest cent

The distance between the buildings is:

D = 413.3 ft

Step-by-step explanation:

Ok, here we have two triangle rectangles, such that these triangle rectangles share a common vertex which is Dale.

One of the triangles, let's call it triangle A, has the catheti:

Distance between Dale and Building A = d1

Height of Building A = 464 ft

The other triangle (triangle B) has the catheti:

Distance between Dale and Building B = d2

Height of building B = 321ft

We want to find the distance between the buildings, which is equal to d1 + d2.

Then we want to find d1 and d2.

For triangle A:

We know that the angle at the vertex where Dale is standing, is 75°

Then the adjacent cathetus is d1, and the opposite cathetus is the height of building A.

Remember that:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Then:

Tan(75°) = (464 ft)/(d1)

d1 = (464 ft)/(Tan(75°)) = 124.3 ft

Now for triangle B, the angle at the vertex where Dale is standing is 48°.

from this vertex, we have d2 as the adjacent cathetus and the height of build B as the opposite cathetus.

Then:

Tan(48°) = 321ft/d2

d2 = (321ft)/(Tan(48°)) = 289ft

Then the distance between the buildings is:

D = d1 + d2 =  124.3 ft +  289ft = 413.3 ft