Mathematics: Enter the values of h and i so that y=x2+6x+10 is in vertex form y=(x++

Enter the values of h and i so that y=x2+6x+10

Ответ:

888914

11.03.2022

$Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\\ \boxed{y=(x+3)^2+1}$

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Ответ:

lylesparks2791

04.01.2020

Mathematics

The answer is five hours

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Enter the values of h and i so that y=x2+6x+10 is in vertex form y=(x++

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