Error Analysis The solution shown for the equation is incorrect. What is the correct solution? What is the error? −6(4−r)=18
−24−6r=18
−6r=42
r=−7
The solution is enter your response here. (Type the value of r.)
What is the error?
A.
The left side of the equation should be −r after dividing each side by −6.
B.
The right side of the equation should be 7 after dividing each side by −6.
C.
The left side of the equation should be −24+6r after distributing.
D.
The right side of the equation should be −6 after subtracting −24 from each side.

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Ответ:

Lia97

28.04.2023

Mathematics

$\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis}$

$\bf \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind.

$\bf \stackrel{parent}{y = \cfrac{1}{x}}\qquad \qquad y=\cfrac{1}{x+\underset{\underset{-5}{\uparrow }}{C}}+\stackrel{\stackrel{-10}{\downarrow }}{D}\implies \cfrac{1}{x-5}-10$

C = -5................. horizontal shift to the right of 5 units.

D = - 10.............. vertical shift downwards of 10 units.

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