¿Es la molaridad de 95g de AlO disueltos en una disolución

Ответ:

kenzie19169

01.11.2021

$x=\frac{7}{12}$

Step-by-step explanation:

We have been given an equation:

$\frac{1}{16}=64^{4x-3}$

In order to solve this equation we will convert the base same on both sides of equation:

we can write $16\text{as}4^2\text{and}64\text{as}4^3$ we get:

$\frac{1}{4^2}={4^3]^{4x-3}$

Now, using $\frac{1}{x^n}=x^{-n}$

Here, n is 3 and x is 4 on l;eft hand side of the above equation:

$4^{-2}=4^{3\cdot (4x-3)}$

$4^{-2}=4^{12x-9}$

We can equate the powers when base are same

Hence, 12x-9=-2

Now, we will solve for x we get:

12x=7

$x=\frac{7}{12}$

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