Estimate the reynolds number for a human swimming in water. approximate the human as a sphere of radius 0.50.5m, swimming at a speed of about 11m/s. the density of water is approximately 1000\text{kg/m}^31000kg/m 3 and its viscosity is 0.001\text{n/m}^2\cdot\text{s}0.001n/m 2 ⋅s.

Re= 5*10^5

Step-by-step explanation:

The numbers are not totally clear as they repeat each other. Under this consideration I will assume the closest values according to the advertised.

r=0.5m

V=1m/s (or) V=11m/s

We know that Reynolds number is given by,

Or for the another velocity

When the ball hit the ground, the height of the ball will be zero. So using the value of h(x) as zero in the given equation, we can find the time in which the ball will hit the ground.

0 = -(x-2)^2 + 16

(x-2)^2 = 16

x-2 = 16

x-2 = 4

x = 6

This means the ball will hit the ground 6 seconds after Amir threw it.