Evaluate 0.53n when n=3 and when n=-3

What you have to do here, is replace n with 3 and multiply 0.53(3) and you will get your first answer. Do the same thing with -3: multiply 0.53(-3) and you will have your second answer. If you do this, I do believe your question will be answered.

5/9

Step-by-step explanation:

What we have in this question are four white balls and 5 red balls.

This is the sample space

[(4w,0R) (4w,1R)(4w,2R)(4w,3R)(4w,4R)(0w,5R)(1w,5R)(2w,5R)

So we have 9 possible sets of events

The event number with the last ball being white = 5

Probability of the last ball drawn being white = 5/9

= 0.56