Evaluate.

(n - 1)!, where n = 3
2
5
6

(n-1) where n= 3

Answer is 2

(n - 1)!

n = 3

( 3 - 1)!

2!

= 1 × 2

= 2

n = 2

(2 - 1)!

1!

= 1

n = 5

(5 - 1)!

4!

= 1 × 2 × 3 × 4

= 24

n = 6

(6 - 1)!

5!

= 1 × 2 × 3 × 4 × 5

= 120

Answered by Gauthmath must click thanks and mark brainliest

4+  2 and 2+  2

Step-by-step explanation:

A rational number is a number that can be written as a ratio. That means it can be written as a fraction, in which both the numerator and the denominator are whole numbers.  

On the other hand, all numbers that are not rational are considered irrational. An irrational number can be written as a decimal, but not as a fraction.

So, let us take two irrational numbers a=4+  2  and b=2+ 2  and we now calculate a−b as follows:  a−b=(4+  2  )−(2+  2)=4+  2 −2−  2 =2=  1 2

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Therefore, the difference of two irrational numbers a and b is 2 and from the above defination of rational numbers, we get that 2 is a rational number.

Hence, the difference of two irrational numbers 4+  2 and 2+  2  is a rational number.