Mathematics: Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) lim x→−5 (x + 5)/ (x^3 + 125 ).

Evaluate the limit, if it exists. (If an answer

juniieb

02.02.2022

$= \dfrac{1}{75}$

Step-by-step explanation:

Given that:

$\lim_{x \to -5} \dfrac{(x+5)}{(x^3+125)}$

(x^3 + 125) = (x+5)(x^2 -5x+25)

Thus;

$= \lim_{x \to -5} \dfrac{(x+5)}{(x+5)(x^2 -5x +25)}$

$= \lim_{x \to -5} \dfrac{1}{(x^2 -5x +25)}$

$= \dfrac{1}{((-5)^2 -5(-5) +25)}$

$= \dfrac{1}{(25 +25 +25)}$

$= \dfrac{1}{75}$

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PatienceJoy

01.01.2021

Step-by-step explanation:

it shows all the numbers less than four while the others show numbers greater than 4

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